If triangle DEF is congruent to triangle
BCA, write the part of triangle BCA
that corresponds to
(i) Angle E
(ii) EF
(iii) Angle F
(iv) DF
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Answer:
Given: ΔDEF≡ΔBCA.
two triangles are congruent
here , D corresponds to B and F corresponds to A
so,
DF↔BA.
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