Question

If triangle MAN ~ Triangle DEF, MA =2cm, area of triangle MAN =16cm and area of triangle DEF = 81cm then find DE

Answer 1

and the corresponding segments are:
∆ A B C ↔ ∆ J K L ∆ ABC ↔ ∆ J K L ∆ A B C ↔ ∆ J K L

AB ↔ JK , BC ↔ KL , AC ↔ JL
The correspondence may be written in more than one way: ∆CAB ↔ ∆LJK is the same
as ∆ABC ↔ ∆JKL.
Example 2:
∆ABC ≅ ∆DEF
Principle 1: (CPCTC) Corresponding parts of congruent triangles are congruent
Principle 2: (Side-Side-Side, SSS) If the three sides of one triangle are congruent to the
three sides of a second triangle, then the triangles are congruent.
Example 3:
A
B
C D
E
F
∠A ≅ ∠D AB ≅ DE
∠B ≅ ∠E BC ≅ EF
∠C ≅ ∠F CA ≅ FD
Since all three sides in ∆ABC are
congruent to all three sides in
∆DEF, then ∆ABD ≅ ∆DEF
A
B
C
E
D F