Question

if triangle PQR similar to triangle DEF angle p = 50° angle E = 82 ° then angle R =?​

Answer 1

given that

ΔPQR ≈ ΔDEF [equation 1 ]

then

        ∠P = ∠D = 50°

         ∠Q = ∠E = 80°

          ∠R = ∠F

from equation 1

      ∠P + ∠Q + ∠R = 180°   [angle sum property]

        50° + 80° + ∠R = 180°

                   130° + ∠R = 180°

                                ∠R = 180° - 130°

                                  ∠R = 50°

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Answer 2

Answer:

Angle R = 48°

Step-by-step explanation:

Given data  

triangle PQR is similar to triangle DEF

and given that ∠P = 50° and ∠E = 82°

here we need to find the ∠R  

from given data ΔPQR～ΔDEF      

In similar triangle the angles of the two triangles are equal

⇒    ∠P   =  ∠D = 50°

       ∠Q  =  ∠E  =  82°    

       ∠ R  =  ∠F    

⇒ we know that sum of the angles in a triangle = 180°          

⇒ In triangle PQR , ∠P + ∠Q +∠R = 180°  

                              50° + 82° + ∠R = 180°

                              ∠R = 180° - 132° = 48°