if triangleABC is right angled at C, then the value of Cos (A + B) is
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Step-by-step explanation:
We know that the sum of all 3 angles in a triangle is 180° .
C=90°
But,
A+B+C=180°
⟹A+B=(180−90)°=90°
We also know that cos90°=0
Hence,
cos(A+B)=0
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