If triangles ABC and DEF are similar and AB=4cm, DE=6cm, EF=9cm and FD=12cm, the perimeter of triangle is:
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If △ABC∼△DEF,AB=4 cm,DE=6 cm,EF=9 cm and FD=12 cm, then find the perimeter of △ABC.
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As per the dimensions give in the questions,
Now, we have to find out the perimeter of △ABC
Let △ABC∼△DEF
So, AB/DE=AC/DF=BC/EF
Consider, AB/DE=AC/DE
4/6=AC/12
By cross multiplication we get,
AC=(4×12)/6
AC=48/6
AC=8cm
Then, consider AB/DE=BC/EF
4/6=BC/9
BC=(4×9)/6
BC=36/6
BC=6cm
Therefore, the perimeter of △ABC=AB+BC+AC
=4+6+8
=18cm.
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