Question

If triangles ABC and DEF are
similar and AB=5cm, DE=9cm,
EF=27cm and FD=18cm, the
perimeter of triangle ABC is


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Answer 1

Answer:

similar triangle then

AB/DE = BC/EF = CA/FD

5/9 = BC/27 = CA/18

BC =

$\frac{5}{9} \times 27 = 15$

CA =

$\frac{5}{9} \times 18 = 10$

so Perimeter of ∆ABC = AB+BC+CA = 5+15+10 = 30 cm.

Ans.

Answer 2

Step-by-step explanation:

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