If triangles ABC is similar to triangle DEF , BC = 4 cm, EF = 5 cm, and ar( ABC) = 80 sq.cm, then ar(DEF) is
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ar(∆ABC)/arDEF=BC^2/EF^2
80/ar(∆DEF)=4^2/5^2
80/ar∆DEF=16/25
ar∆DEF=(25×80)/16=25×5=125sq.cm
we know that ratio of area of two similar triangles is equal to ratio of square of their corresponding sides.
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