if trianlge ABC is similar to triangle DEF such that 2AB=DE and BC=8cm,then find EF
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it will be 16 centimetre
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Answer:
given : ∆ABC ~ ∆DEF
DE = 2AB and BC = 8 cm
therefore, AB/DE = BC/EF
=> AB/2AB = 8/EF [since, DE=2AB]
=> 1/2=8/EF
therefore , EF= 16 cm
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