If truth and lie are zeroes of the polynomial px2
+ qx + r, (p 0) and zeroes are
reciprocal to each other,
(i) Find the relation between p and r. (ii) Which value do you learn from this question?
Answers
Answered by
96
Truth and lie are zeros of the polynomial Px² + qx + r , ( P ≠ 0) ,.and zeros are reciprocal to each other . Means truth = 1/lie or, truth.lie = 1
Use product of zeros = constant/coefficient of x²
Truth.lie = r/p
1 = P/r ⇒ P = r
Hence, relation between p and r : P = r
Now put P = r in given equation
rx² + qx + r = 0
Discriminant , D = b² - 4ac = q² - 4r.r
D = q² - 4r²
When zeros is real , D ≥ 0
q² ≥ 4r² , hence for real value q² must be greater than equal to 4r² .
Use product of zeros = constant/coefficient of x²
Truth.lie = r/p
1 = P/r ⇒ P = r
Hence, relation between p and r : P = r
Now put P = r in given equation
rx² + qx + r = 0
Discriminant , D = b² - 4ac = q² - 4r.r
D = q² - 4r²
When zeros is real , D ≥ 0
q² ≥ 4r² , hence for real value q² must be greater than equal to 4r² .
Answered by
12
Answer:
Truth and lie are zeros of the polynomial Px² + qx + r , ( P ≠ 0) ,.and zeros are reciprocal to each other . Means truth = 1/lie or, truth.lie = 1
Use product of zeros = constant/coefficient of x²
Truth.lie = r/p
1 = P/r ⇒ P = r
Hence, relation between p and r : P = r
Now put P = r in given equation
rx² + qx + r = 0
Discriminant , D = b² - 4ac = q² - 4r.r
D = q² - 4r²
When zeros is real , D ≥ 0
q² ≥ 4r² , hence for real value q² must be greater than equal to 4r² .
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