Question

if tthe zeroes of the quadratic polynomial x²+(a+1) x+b are 2 and -3 then​

Answer 1

Answer:

a=0, b=-6

Step-by-step explanation:

if 2 is zero of the quadratic polynomial x²+(a+1) x+b

then (2)^2+(a+1)(2)+b= 0

4+2a+2+b=0

2a+b+6=0------->I

if -3 is zero of the quadratic polynomial x²+(a+1) x+b then (-3)^2+(a+1)(-3)+b= 0

9-3a-3+b = 0

-3a+b+6= 0------->II

equation I - equation II

2a+3a+b-b+6-6=0

5a=0

a=0

from equation I

2×0+b+6=0

b+6=0

b=-6

a=0, b=-6

required quadratic polynomial is x²+ x-6