If twelfth term of an A.P is 30, then the sum of its fifth, twelfth and nineteenth term is 90 30 60 45
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Answer:
- sum of fifth, twelfth and nineteenth terms of AP is 90 .
Step-by-step explanation:
[ nth term of an AP is given by ; aₙ = a + ( n- 1 ) d ]
Let us take first term of AP = a
and. common difference of AP = d
then,
Given that, twelfth term of AP is 30
so,
- a₁₂ = 30
- a + 11 d = 30 .... eqn (1)
Now,
we need to find sum of its fifth , twelfth and nineteenth terms
- a₅ + a₁₂ + a₁₉ = ?
so,
Let, a₅ + a₁₂ + a₁₉ = x
→ x = a₅ + a₁₂ + a₁₉
→ x = a + 4 d + a + 11 d + a + 18 d
→ x = 3 a + 33 d
→ x = 3 ( a + 11 d )
[ using equation (1) ]
→ x = 3 ( 30 )
→ x = 90
therefore,
sum of fifth, twelfth and nineteenth terms of AP is 90 .
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