Question

If twice a certain number is added to the product of 6 and the reciptocal of 3 more than that number and 4, the result is 13. Find the number

Answer 1

Step-by-step explanation:

Let the number be x

According to the question,

x+(1/x)*2=11/3

or x+2/x=11/3

or (x^2+2)/x=11/3

or 3x^2+6=11 x

or 3x^2 - 1 1x +6 = 0

This is a quadratic equation. Let us extract its roots.

[x= {-b +/-✔(b^2 - 4ac )}2a]

x={11 +/-✔(121 - 4*3*6)}/2*3

or x= (11 +/-✔49) /6

or x=3 Or x =2/3 Answer

hope this helps ☺️