if twice the area of a smaller square is subtracted from the area of a larger square is equal to 14 cm however if twice the area of the larger square is added to 3 times the area of the smaller square the result is 203 cm determine the sides of the two squares
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let the side of the smaller square = a cm
side of the larger square = b cm
twice the area of a smaller square is subtracted from the area of the larger square
=14 cm²
b² - 2a² =14-----(1)
twice the area of the larger square is add to three times the area of the smaller square =203 cm²
2b² + 3a²=203---(2)
multiply (1) with 2 and subtract it from (2)
2b²+3a²=203
2b²-4a²= 14
____________
7a²=175
a²= 175/7
a²=25
a = 5 cm
substitute a =5 in (1)
b²-2a²=14
b²-2*5²=14
b²-50=14
b²=14+50
b²=64
b=8 cm
larger square side = b =8cm
smaller square side = a = 5 cm
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side of the larger square = b cm
twice the area of a smaller square is subtracted from the area of the larger square
=14 cm²
b² - 2a² =14-----(1)
twice the area of the larger square is add to three times the area of the smaller square =203 cm²
2b² + 3a²=203---(2)
multiply (1) with 2 and subtract it from (2)
2b²+3a²=203
2b²-4a²= 14
____________
7a²=175
a²= 175/7
a²=25
a = 5 cm
substitute a =5 in (1)
b²-2a²=14
b²-2*5²=14
b²-50=14
b²=14+50
b²=64
b=8 cm
larger square side = b =8cm
smaller square side = a = 5 cm
mark me as brainliest
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