if twice the second term of an ap is equal to 5 times the 5th term of the AP show that seven term is zero
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formula of ap is a+(n-1)d
let twice the second term of an ap be x2
x2=a+d
x2=5(x5)
2(a+d)=5(a+4d)
x5 is the 5th term of ap
2a+2d=5a+20d
-3a=18d
a= -6d
x7 is seventh termin ap
a+6d
-6d+6d=0
proved
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