Math, asked by Itznikhilhere, 8 months ago

if twice the sons age in years is added to the age of his father the sum is 90. If twice the father's age in years is added to the age of son is 120. Find their ages.

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Answered by shubhamsasane32

Answer:

let the age of the father be(y)

let the son age be (x)

2x+y=90------eq 1

x+2y=120------eq2

multiply eq 1 by 2

4x+2y=180----eq3

substract eq1 from eq3

3x=60

x=20 is the age of the son

put x=20 in eq 1

y= 50 is the age of the father

Step-by-step explanation:

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Answered by Anonymous

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• let the age of the father be x and the age of the son be y

according to the conditions,

2y+x=70 ..............(1)

2x+y=95 ..............(2)

multiplying equation (1) into 2 we get

subtracting equation (2) from equation (3)

4y+2x=140 .........(3)

y+2x= 95

---------------

3y = 45

y=15 ..................(4)

substituting (4) in (2) we get

15 +2x=95

2x=80

x=40.

Therefore the age of the father is 40yrs and that of the son is 15

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if twice the sons age in years is added to the age of his father the sum is 90. If twice the father's age in years is added to the age of son is 120. Find their ages.​

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if twice the sons age in years is added to the age of his father the sum is 90. If twice the father's age in years is added to the age of son is 120. Find their ages.