Math, asked by Itznikhilhere, 2 months ago

if twice the sons age in years is added to the age of his father the sum is 90. If twice the father's age in years is added to the age of son is 120. Find their ages.​

Answers

Answered by a8486234
1

Answer:

40 ; 80

Step-by-step explanation:

let the son's age be x

and Father's age be 2x

then,

x + 2x = 120

3x = 120

x = 120/3

x = 40

son's age = x = 40

Father's age = 2x = 2× 40 = 80

Answered by MrImpeccable
7

ANSWER:

Given:

  • Twice the sons age added to father's age is 90
  • Twice the father's age added to son's age is 120.

To Find:

  • Ages of son and father

Solution:

Let the age of son and father be x and y respectively.

So, we are given that,

⇒ Twice the sons age added to father's age = 90

So,

⇒ 2x + y = 90 ------(1)

And,

⇒ Twice the father's age added to son's age = 120.

So,

⇒ x + 2y = 120 ------(2)

Multiplying, (2) with 2,

⇒ (x + 2y = 120) × 2

⇒ 2x + 4y = 240 ------(3)

Subtracting (1) from (3),

⇒ 2x + 4y - 2x - y = 240 - 90

⇒ 3y = 150

⇒ y = 150/3

⇒ y = 50

Substituting value of y in (1),

⇒ 2x + 50 = 90

⇒ 2x = 90 - 50

⇒ 2x = 40

⇒ x = 20

Hence, age of son and father is 20 years and 50 years respectively.

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