if twice this area of a smaller square subtracted from the area of largest square the result is 14 cm square however it twice the area the largest square is added to 3 times the area smallest square the result is 203 CM square determine the side of the two square
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here is your answer
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let the length of side of 1st square (smaller one) be "a" and that of the other (large square) be "b"
b²-2a²=14-----(1)
2b²+3a²=203------(2)
from (1) we have,
b²=14+2a²
putting the value of b²in (2) we get,
2(14+2a²)+3a²=203
28 +4a²+3a²=203
7a²=175
a²=25
a=5(on neglecting the -tive value)
b²=14+2(25)=14+50=64
b=8(on neglecting the -tive value)
hence a=5cm b=8cm
========================
i hope u understand
here is your answer
==================
let the length of side of 1st square (smaller one) be "a" and that of the other (large square) be "b"
b²-2a²=14-----(1)
2b²+3a²=203------(2)
from (1) we have,
b²=14+2a²
putting the value of b²in (2) we get,
2(14+2a²)+3a²=203
28 +4a²+3a²=203
7a²=175
a²=25
a=5(on neglecting the -tive value)
b²=14+2(25)=14+50=64
b=8(on neglecting the -tive value)
hence a=5cm b=8cm
========================
i hope u understand
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