If TWO^2 = THREE where the alphabets are single-digit integers then find T + W + O
Answers
If TWO^2 = THREE where the alphabets are single-digit integers then T + W + O = 12
Complete Question:
If TWO^2 = THREE where the alphabets are single-digit integers then find T + W + O?
a) 12
b) 25
c) 18
d) 29
Solution:
It is given in the question that the alphabets are single-digit integers so we need to take single-digit integers from 0 to 9.
when we solve by taking single-digit integers(by adding the same integers thrice) from 0 to 9 then the answer cannot be 25 or 29.
So the answer maybe is 18 or 12.
Let us consider the single digit number 6
=> T + W + O
=> 6 + 6 + 6
=> 18
Now, divide it with 2
=> 18/2 = 9
but the number 9 is not there in the given options. so, it is not the required answer.
12 is the required answer. let's see how?
Let us consider the single-digit number 8
=> T + W + O
=> 8 + 8 + 8
=> 24
Now, divide it with 2
=> 24/2
=> 12
Another way:
It's given in the question that 2^2 = 3
generally, 2^2 is 4.
So, by writing the number 4 threetimes, we will get 12 as the answer.
Hence, the required answer is Option -A => 12
Given : TWO² = THREE where the alphabets are single-digit integers
To Find : T + W + O
Solution:
TWO² = THREE
alphabets are single-digit integers
TWO is three digit numbers
and THREE is 5 digit numbers
Hence T must be 1
T = 1
Now trying different possible combination
TWO are different digits
Hence can be 102 , 103 , 104 , 105 , 106 , 107 , 108 , 109 , 120 , 123 , 124 , 125 , 126 , 127 , 128 , 129 , 130 , 132 , 134 , 135 , 136 , 137 , 138 , 139 , 140
142² is 6 digit number
number ending with 0 are not possible as then O = 0 and E = 0
Hence only 138² = 19044 end with repeated digit
T = 1 W = 3 , O = 8
H = 9 , R = 0 , E = 4
T + W + O = 1 + 3 + 8 = 12
T + W + O = 12
learn More:
Each letters in the picture below, represents single digit
brainly.in/question/23230358
brainly.in/question/23978359