Question

If TWO^2 = THREE where the alphabets are single-digit integers then find T + W + O​

Answer 1

If TWO^2 = THREE where the alphabets are single-digit integers then T + W + O = 12

Complete Question:

If TWO^2 = THREE where the alphabets are single-digit integers then find T + W + O?

a) 12

b) 25

c) 18

d) 29

Solution:

It is given in the question that the alphabets are single-digit integers so we need to take single-digit integers from 0 to 9.

when we solve by taking single-digit integers(by adding the same integers thrice) from 0 to 9 then the answer cannot be 25 or 29.

So the answer maybe is 18 or 12.

Let us consider the single digit number 6

=> T + W + O

=> 6 + 6 + 6

=> 18

Now, divide it with 2

=> 18/2 = 9

but the number 9 is not there in the given options. so, it is not the answer.

12 is the required answer. let's see how?

Let us consider the single-digit number 8

=> T + W + O

=> 8 + 8 + 8

=> 24

Now, divide it with 2

=> 24/2

=> 12

Another way:

It's given in the question that 2^2 = 3

generally, 2^2 is 4.

So, by writing the number 4 three times, we will get 12 as the answer.

Hence, the required answer is Option -A => 12

Answer 2

Given :  TWO² = THREE where the alphabets are single-digit integers

To Find : T + W + O​

Solution:

TWO² = THREE

alphabets are single-digit integers

TWO is three digit numbers

and THREE is 5 digit numbers

Hence T must be 1  

T = 1

Now trying different possible combination

TWO are different digits

Hence can be  102 , 103 , 104 , 105 , 106 , 107 , 108 , 109 , 120 , 123 , 124 , 125 , 126 , 127 , 128 , 129 , 130 , 132 , 134 , 135 , 136 , 137 , 138 , 139 , 140

142² is 6 digit number

number ending with 0 are not possible as then O = 0 and E = 0

Hence only   138² = 19044 end with repeated digit

T = 1  W = 3  , O = 8

H = 9 , R = 0 , E = 4

T + W + O​ = 1 + 3 + 8 = 12

T + W + O  = 12

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