Question

If two adjacent angles are (5x-2) and (2x+42) then find the value of x

Answer 1

Solution :

Let us assume that the figure is that of a parallelogram .

The two adjacent angles are 5x-2 and 2x+42 .

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In a parallelogram, the adjacent angles are supplementary i.e, add upto 180°

>> 5x - 2 + 2x + 42 = 180

>> 7x - 40 = 180

>> 7x = 220

>> x = 220/7 = 31.4285714286° approx

This is the required answer .

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Answer 2

Answer:

Question :-

• If two adjacent angles are (5x-2) and (2x+42) then find the value of x.

Given :-

• If two adjacent angles are (5x-2) and (2x+42) .

Find Out :-

• Find the value of x.

Solution :-

We have :

☯ First adjacent angles is (5x-2)

☯ Second adjacent angles (2x+42)

As we know that :

$\red{ \boxed{\sf{\bigstar\: Sum\: of\: any\: two\: adjacent\: angles_{(Parallelogram)} =\: 180^{\circ}}}}$

So, according to the question or ATQ :-

➙ (5x - 2) + (2x + 42) = 180°

➙ 5x - 2 + 2x + 42 = 180°

➙ 5x + 2x + 42 - 2 = 180°

➙ 7x + 40 = 180°

➙ 7x + 40 = 180°

➙ 7x = 180° - 40

➙ 7x = 140°

➙ x = $\sf \cancel{\dfrac{140^{\circ}}{7}}$

➙ x = 20°

Henceforth, the value of x is 20° .