if two adjacent angles of rhombus are (5x+20)° and (3x-8) °, then find all the angles of rhombus
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Sum of adjacent angles of a rhombus = 180°
According to condition,
(5x+20)+(3x-8) = 180
or, 8x+12 = 180
or, 8x = 180-12
or, 8x = 168
or, x = 168/8
or, x = 21
(5x+20)° = {(5×21)+20}° = (105+20)° = 125°
(3x-8)° = {(3×21)-8}° = (63-20)° = 55°
Since, the opposite angles of a rhombus are equal, all its angles are 125°, 55°, 125° and 55°.
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