Question

if two adjacent sides of a parallelogram are 22 cm and 13cm,find its perimeter​

Answer 1

Answer:

Area of triangle =  

s(s−a)(s−b)(s−c)

​  

 

Area of parallelogram=2× Area of triangle formed by the adjacent sides and the diagonal  

Sides are 17cm,12cm,25cm

Semi perimeter(s)=  

2

12+17+25

​  

=  

2

54

​  

=27cm

Area =  

27(27−12)(27−17)(27−25)

​  

 

⇒A=  

27⋅15⋅10⋅2

​  

 

⇒A=  

3×3×3×3×5×2×5×2

​  

 

⇒A=3×3×5×2

⇒A=90cm  

2

 

∴ Area of parallelogram =2(90)=180cm  

2

.

h=?; b=12cm

A=b×h

⇒180=12×h

⇒  

12

180

​  

=h

∴h=20cm

∴ Length of altitude =h=20cm.

Step-by-step explanation:

please mark this answer as a brainliest answer.

Answer 2

Answer:

Hence, value of perimeter of parallelogram will be 70 cm

Step-by-step explanation:

In context to question asked,

We have to determine the value of perimeter of the parallelogram.

As per question,

Parallel sides of parallelogram are - 22 cm and 13 cm

As we know that,

• Opposite sides of parallelogram are parallel and equal.
• Perimeter of any figure can be determined by adding the length of sides of outer border of the figure.

So, for determining the value of perimeter of parallelogram we will use the formula - $Perimeter = 2 (l +b) = 2 (Sum\: of \:both \:sides)$

So, for determining the value of perimeter of parallelogram we will put the value of sides given in the question in above formula,

Thus we will get,

$Perimeter = 2 (22+13) = 2 \times 35 = 70\:cm$