Math, asked by ajinkyasupate7, 9 months ago

if two altitude of a triangle are equal, prove that it is an isosceles triangle​

Answers

Answered by Aradhya3210
53

Answer:

AC=BC therefore, ∆ABC is an isosceles triangle

Step-by-step explanation:

GIVEN: In ∆ABC, Altitudes AD and BE are equal

TO PROVE:. AB=BC

PROOF:. In ∆BEC & ∆ADC

BE=AD(GIVEN)

<C=<C(COMMON)

<E=<D(EACH 90•

∆BEC~=∆ADC(AAS). .....(i)

Similarly, ∆BAE~=∆ABD. .....(ii)

Adding (I) & (ii)

∆BAC~=∆ABC

By C.P.C.T.

AC=BC

HENCE,PROVED ∆ABC is an isosceles triangle

Answered by ritvikriaan3322
1

Answer:

two altitude of a triangle are equal, prove that it is an isosceles triangle

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