if two altitude of a triangle are equal, prove that it is an isosceles triangle
Answers
Answered by
53
Answer:
AC=BC therefore, ∆ABC is an isosceles triangle
Step-by-step explanation:
GIVEN: In ∆ABC, Altitudes AD and BE are equal
TO PROVE:. AB=BC
PROOF:. In ∆BEC & ∆ADC
BE=AD(GIVEN)
<C=<C(COMMON)
<E=<D(EACH 90•
∆BEC~=∆ADC(AAS). .....(i)
Similarly, ∆BAE~=∆ABD. .....(ii)
Adding (I) & (ii)
∆BAC~=∆ABC
By C.P.C.T.
AC=BC
HENCE,PROVED ∆ABC is an isosceles triangle
Answered by
1
Answer:
two altitude of a triangle are equal, prove that it is an isosceles triangle
Similar questions