Question

if two and three zeros of polynomial 3x² - 2kx + 2m, then find the value of k and M​

Answer 1

when x=2 then -

3(2)^2 - 2k(2) + 2m =0

12 - 4k + 2m = 0

4k-2m=12 ---------------> Eq1

when x=3 then-

3(3)^2 - 2k(3)+2m=0

27-6k+2m=0

6k-2m=27 ------------>Eq2

on subtracting Eq1 from Eq2 we get -

k=-15/2.

Hope this helps.

please mark as BRANLIEST.

Answer 2

Easy way
(x-2)(x-3)=0
x^2 - 5x + 6 = 0
3x^2 - 15x + 18 = 0
Comparing with the given polynomial
2k=15 and 2m=18
So k=15/2 and m=9