Question

if two angles are complementary and one is 10 less than three times the other then find the angle​

Answer 1

Answer:

Step-by-step explanation:80˚3,190˚3

Explanation:

m∠1=x

m∠2=2x+10

Since the angles are complementary,

m∠1+m∠2=90˚

Thus,

x+(2x+10)=90˚

3x+10=90˚

3x=80˚

x=m∠1=803

The other angle is 2x+10, or

m∠2=2(803)+10=1603+303=1903

Answer link

Answer 2

Step-by-step explanation:

Given :Two angles are complementary, means their sum is 90 degree.Let the two angles be a and b.

a + b = 90 degree ......(1)

It is given in the question that one angle is ten less than three times the other angle, say

b = 10 less than 3* a( 3 times 'a' means 3 multiplied by a)

b= 3*a - 10 ......(2)

Now substitute the value of 'b'in (1)

a + b = 90

a + 3*a- 10 = 90 ( coefficient of a is 1 ,so 1*a +3a= 4*a)

4*a = 90 + 10

4*a =100

a = 100/4

a = 25

One angle 'a' is 40 degrees

N ow to find the value of other angle 'b', put in the value of 'a' in the equation (2)

b= 3*a - 10

b= 3*25 - 10

b= 75- 10

b= 65 degrees

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