if two angles are supplementary angles and ones is 30 degree less than twice the other, find the angles
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Let one Angle be x,
Thus the other angle = 2x -30
We know,
Sum of supplementary angles = 180 deg
ATQ,
x + 2x - 30 = 180
3x - 30 = 180
3x = 210
x = 70 degrees
2x-30 = 140-30 = 110 degrees
Thus, the reqd angles are 70 deg and 110 deg respectively :)
Thus the other angle = 2x -30
We know,
Sum of supplementary angles = 180 deg
ATQ,
x + 2x - 30 = 180
3x - 30 = 180
3x = 210
x = 70 degrees
2x-30 = 140-30 = 110 degrees
Thus, the reqd angles are 70 deg and 110 deg respectively :)
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