Question

if two angles of a quadrilateral 77 degree and 57 degree and out of the remaining two angles one angle is 10 degree smallest than the other find the angle

Answer 1

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The two angles of Quadrilateral are 77° and 57° .
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Let the remaining angles be x° and x-10° .

We know that the sum of all the angles of a quadrilateral is 360° .
Hence,

x + x-10 + 57 + 77 = 360°
2x +124 = 360
2x = 236
x = 118°

Then first angle = 118°
Second angle = _118- 10 = 108° _
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