Question

if two angles of a quadrilateral are 77 and 57 , and out of the remaing two angles , one angle is 10 smaller than the other , find these angles

Answer 1

the sum of all angles in a quadrilateral is 360
so..2 angles are 77 and 57
let the other angle be x
and the other angle be x-10
sum of all angles is 360
77+57+x+x-10=360
124+2x=360
2x=360-124
2x=236
x=236/2
x=118
x-10=108

Answer 2

angle-1 = 77°
angle-2 = 57°
Let angle-3 be "x"
So, angle-4 = x-10
We know that sum of all angles in a quadrilateral is 360°
So, angle-1 + angle-2 + angle-3 + angle-4 = 360°
77° + 57° + x + x-10 = 360°
134° - 10° + 2x = 360°
124° + 2x = 360°
2x = 360° - 124°
2x = 236°
x = 236°/2
x = 118°

Hence, angle-3 = x = 118°
angle-4 = x-10 = 118°-10 = 108°