If two angles of a triangle are equal then prove that sides opposite those angles are also equal.
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Hola
Here is your answer Friend!
This thereom is also known as Isoceles thereom.
Here is the answer -
Given - In ∆ABC Angle B = Angle C
To prove - Angles opposite to equal sides are equal that is
AB = AC
Construction - Draw a perpendicular line through A and Mark that perpendicular line as AD
Proof - In ∆ ADB and ∆ ADC
Angle B = Angle C.. - Given
AD = AD .. Common Side
Angle ADB = Angle ADC.. Each 90° aa construction AD perpendicular to BC.
Thus, ∆ADB Congruent to ∆ ADC
By ASA test.
Therefore AB = AC
- C. P. C.T
Hence Proved!
Hope it helps!
Here is your answer Friend!
This thereom is also known as Isoceles thereom.
Here is the answer -
Given - In ∆ABC Angle B = Angle C
To prove - Angles opposite to equal sides are equal that is
AB = AC
Construction - Draw a perpendicular line through A and Mark that perpendicular line as AD
Proof - In ∆ ADB and ∆ ADC
Angle B = Angle C.. - Given
AD = AD .. Common Side
Angle ADB = Angle ADC.. Each 90° aa construction AD perpendicular to BC.
Thus, ∆ADB Congruent to ∆ ADC
By ASA test.
Therefore AB = AC
- C. P. C.T
Hence Proved!
Hope it helps!
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