Question

If two angles of a triangle are equal then prove that the sides opposite to those sides are also equal

Answer 1

Answer:

Proved

Step-by-step explanation:

Let ABC be a Δ such that ∠B= ∠C

Construct: AD perpendicular to BC

Now in  ΔADC and ΔABD

∠B= ∠C

One side AD is common

and ∠D is right angle = 90°

now this two angles and a side is equal the two triangles are congruent to each other by ASA postulate

Therefore AB=AC by CPCTC( corresponding parts of congruent triangles are congruent)