Question

If two angles of a triangle are equal then the sides opposite to them are also equal prove this statement.​

Answer 1

Answer:

Given :

A △ABC in which ∠B=∠C.

To prove :

AB=AC

Construction :

Draw the bisector of ∠A and let it meet BC at D.

Proof  :

In △s ABD and ACD,

∠B=∠C

∠BAD=∠CAD

AD=AD

So, by AAS criterion of congruence,

△ABD≅△ACD

⟹AB=AC