if two angles of a triangle are in ratio 4:7 and third angle is and third sngle is 48 degree, find the other angles
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let the ratio of 2 angle=4x&7x
the third angle =48°
sum of all angles=180°
180°-48°=132°
A/Q
4x+7x=132°
x=132÷11
x=12
1st angle =4x =4×12=48
2nd angle=7x=7×12=84 ans
the third angle =48°
sum of all angles=180°
180°-48°=132°
A/Q
4x+7x=132°
x=132÷11
x=12
1st angle =4x =4×12=48
2nd angle=7x=7×12=84 ans
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