Question

If two angles of a triangle are unequal than the side opposite smaller angle is
Guys please the answer​

Answer 1

Answer:

Given: △ABC, ∠ACB>∠ABC

To Prove: AB>AC

Construction: Make a point D on AB such that ∠ACD=∠ADC and join DC

In △ACD,

∠ACD=∠ADC

AD=AC (Sides opposite equal angles)

But AB=AD+DB

thus, AB>AD

but AD=AC

Hence, AB>AC

Thus, sides opposite smaller angles are smaller

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Answer 2

Answer:

They are: Theorem 36: If two sides of a triangle are unequal, then the measures of the angles opposite these sides are unequal, and the greater angle is opposite the greater side.

Step-by-step explanation:

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