Question

if two angles of quad are 77 and 57 and out of the remaining two angles one angle is 10 smaller than another
find these angles?
plz help

Answer 1

Two angles are=77° and57°
LET third angle=x°
Fourth angle 10 less than third=(x-10)°

Sum of all angle in Quadrilateral is=360°
A/Q
77+57+x+(x-10)=360
134+x+x-10=360
124+2x=360
2x=360-124
2x=236
x=236/2
x=118

Third angle=118°
Fourth angle=118-10=108°

All angles=77°,57°,118°,108°

Answer 2

Solution:-
given by, two angle of quad are 77 and 57.
let the third angle is y ,
according to question forth angle is y-10
we have,
we know that
sum of all quad angle is = 360 degree
■ 77+57+y+(y-10) = 360
= 134 + 2y -10 = 360
= y = 236/2
the third angle is 118
forth angle is 118 -10 = 108