Question

If two angles (x+27)digress, (3x_39)digress are supplementary find 'x'

Answer 1

Hello!

$\sf ATQ,$

$\sf (x+27)+(3x-39) = 180 \\ \\ \implies \sf x+27+3x-39 = 180 \\ \\ \implies \sf 4x -12 = 180 \\ \\ \implies \sf 4x = 192 \\ \\ \implies \sf x = \dfrac{192}{4} \implies \boxed{\red{\bf{x = 48^{\circ}}}}$

Cheers!

Answer 2

$\bf \large \it \: Hey \: User!!!$

given (x + 27) and (3x - 39) are supplementary.

we have to find the value of x.

we know that the sum of two supplementary angles is 180°

therefore x + 27 + 3x - 39 = 180°
>> 4x - 12 = 180°
>> 4x = 180 + 12
>> 4x = 192
>> x = 192/4
>> x = 48°

hence, the value of x is 48°

$\bf \large \it{Cheers!!!}$