If two angls are supplementry angles snd one angle is 5° more than 4thtimes the other. Find the angles
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Let one of the angles be x.
then according to the question
Other angle will be (4x+5)
Sum of supplementery angles = 180°
x + (4x+5) = 180°
5x + 5 = 180°
5x = 180-5 = 175°
x = 175/5 = 35°
Angles will be
x = 35°
4x+5 = 4×35 +5 = 145°
then according to the question
Other angle will be (4x+5)
Sum of supplementery angles = 180°
x + (4x+5) = 180°
5x + 5 = 180°
5x = 180-5 = 175°
x = 175/5 = 35°
Angles will be
x = 35°
4x+5 = 4×35 +5 = 145°
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