If two apposite angles of a parallelogram are (63-3x) degree and (4x-7) degree find all the angles of the parallelogram
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opposite angle of parallelogram are equal so
63-3x=4x-7
70=7x
x=10
one angle is 33 and second is also 33
first angle and third angle are supplementary
so third angle is 147 and fourth is also 147
hope you easily understand and like it
63-3x=4x-7
70=7x
x=10
one angle is 33 and second is also 33
first angle and third angle are supplementary
so third angle is 147 and fourth is also 147
hope you easily understand and like it
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