Question

if two aps have the same common difference and difference between their 48th , then the difference between their 96th term will be​

Answer 1

Step-by-step explanation:

Given that their 100th term's difference is 100

Let the first no. of first series be a1 and second series be a2.

then, a100(1)−a100(2)=100 --- 1)

For 1st series ---- a100=a1+99d

    2nd series ---- a100=a2+99d

Put these values in (1)

then, 

a1+99d−(a2+99d)=100

a1+99d−a2−99d=100

therefore, a1−a2=100 ---2)

Then, the difference between their 1000th terms is

for 1st series --- a1000=a1+999d

for 2nd series --- a1000=a2+999d

their 100th terms difference is

a1000(1)−a1000(