Question

if two bodies having masses 25kg and 20gm are placed at 20cm distance find the force between them given G= 6.67*10 MINUS RAISE TO POWER 11 N-m square/kg square

Answer 1

$Force = \frac{GMm}{d^2} \\ \\ = 6.67 * 10^{-11} * \frac{25*20*10^{-3}} {0.2^2} = 8.3 * 10^{-10} Newtons$

Answer 2

Given, m1=25kg
m2=20g=(20/1000)kg=0.02Kg
distance, r= 20cm=(20/100)m= 0.2m
G=$6.67*10^{-11} Nm^2 kg^{-2}$
We know, $F=G \frac{m_1*m_2}{r^2}$
Substituting the values of m1,m2,G & r
$F= \frac{6.67*10^{-11}*25*0.02}{(0.2)^2}$
$F=83.375*10^{-11} N$
$F=8.3375*10^{-10} N$