Question

If two bodies of different masses is m1 and m2 are dropped from different heights h1 and h2 then the ratio of their time taken to reach the ground is a)h1:h2 b]h2/h1 c]sqrt h1:sqrt h2 d]h1^2:h2^2

Answer 1

Though the motion of both the bodies is free fall.
Using - h=ut+1/2(-g)t square
Here s is - s and as it is free fall a is - g
Here u=0 as body is initially at rest

Eqn. Will be h1=1/2g t1 square
And h2=1 /2 g t2 square

Therefore the ratio will be whole root over 2gh1/2gh2 which is equal to root over h1/h2

Answer 2

c) √h1:√h2 is the right option.
use h=ut+1/2at²
h1 = 1/2a(t1)² [u=0]
t1 = √(2ah1)
similarly t2 =√(2ah2)
dividing t1 by t2 , we get
t1:t2 = √h1:√h2