If two bodies of different masses m1 and m2 are dropped from a height a and b , give the ratio of time taken by the two bodies to drop through these distance ?
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Hey there,
Basically,the time taken does not
depend on mass.
Time taken for constant
acceleration,g and u=0 is given by
2nd eqn of motion
=>s=1/2gt^2=>t=√(2s/g)
T1=√(2a/g),T2=√(2b/g)
T1:T2=√2a/√2b=a/b
Hope it helps
Basically,the time taken does not
depend on mass.
Time taken for constant
acceleration,g and u=0 is given by
2nd eqn of motion
=>s=1/2gt^2=>t=√(2s/g)
T1=√(2a/g),T2=√(2b/g)
T1:T2=√2a/√2b=a/b
Hope it helps
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