if two bulbs rated 2.5 watt 110 volt and 100 watt 110 volt are connected in series to a 220 volt supply tthen
a) 100W bulb will fuse
b) 2.5W bulb will fuse
c) both will fuse
d) Non will fuse
e) none of these
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answer : option (b) 2.5 W bulb will fuse.
explanation : first of all, find resistance of each bulb, R = V²/P
for first bulb ( P = 2.5 watt, V = 110 volts)
so, R1 = (110)²/(2.5) = 12100/2.5
= 4840 ohm.
for second bulb (100 watt, 110 volts)
so, R2 = (110)²/(100)
= 121 ohm
both bulbs are joined in series combination. so, Req = R1 + R2
= 4840 + 121
= 4961 ohm
so, current passing through circuit , I = (220 volts)/(4861 ohm)
= 220/4861 ≈ 0.045 A
now current passing through first bulb, I1 = P1/V1 = (2.5 watt)/110 volts
≈ 0.02272 A
and current through second bulb, I2 = P2/V2 = (100 watt)/110 volts
≈ 0.909A
here I > I1
The total current is bigger than the allowed value on the first bulb, so the 2.5watt bulb will fuse.
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