Question

If two capacitor C1 and C2 are connected in series, then derive an equation for their equivalent capacitance?

Answer 1

Explanation:

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Answer 2

Answer:

If two capacitor C1 and C2 are connected in series, then equivalent capacitance is 1/C1 + 1/C2

Explanation:

• When the negative plate of one capacitor is connected to the positive plate of second and negative of the second is corrected to the positive of the third and so on the capacitor acid to be connected in series.
• In series combination, charges on each capacitor is same but potential difference across the capacitors may be different.
• The electrical capacitance of a conductor is the measure of its ability to hold electrical charges. The capacitance of a conductor may be defined as the charge required to increase the potential of the conductor by unit amount.
• The potential difference across the various capacitors are
• V1 = Q/C1 and V2 = Q/C2
• For series combination, sum of these potential difference is equal to applied potential difference.
• V = V1 + V2

$V = \frac{Q}{C1} + \frac{Q}{C2} \\ \frac{V}{Q} = \frac{1}{C1} + \frac{1}{C2} \\ \frac{1}{C} = \frac{1}{C1} + \frac{1}{C2}$

• C is the equivalent capacitance.