if two cards are drawn from a pack of 52 cards then the prbability of getting both red or both kings is
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Step-by-step explanation:
Clearly,
n (S) = n (S)=
52C2=
(52×51)2
= 1326
Let E1
= event of getting both red cards
E2
= event of getting both kings
Then, E1
∩
E2
= event of getting 2 kings of red cards.
∴ n (E1)=26C2=(26×25)(2×1)
= 325 and
n (E2)=4C2=(4×3)(2×1)
= 6
n(E1∩E2)=2C2=1
∴P(E1)=n(E1)n(S)=3251326
and
P(E2)=n(E2)n(S)=61326
P(E1∪E2)=11326
∴ P (both red or both kings)
=P(E1∪E2)=P(E1)+P(E2)−P(E1∪E2)=(3251/326+6/1326−11326)=330/1326=55/221
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