Question

If two cards are drawn simultaneously from a pack of well shuffled cards, then find the probability of both being numbered cards?

Answer 1

Step-by-step explanation:

Let S be event of drawing two cards simulteneously.

Total number of outcomes, n(S)=52.

Let E be event of geting both cards as numbers.

E={spades 2-10, clubes 2-10, diamonds 2-10, hearts 2-10}

Total number of numbered cards is n(E)=36

probability of event S:

P(S)=n(E)/n(S)=36/52=9/13=0.69.

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Answer 2

Answer: 0.475

Step-by-step explanation:

Total cards = 52

Numbered cards of spade = 9 (2-9)

Numbered cards of club = 9 (2-9)

Numbered cards of diamond = 9 (2-9)

Numbered cards of heart = 9 (2-9)

Total numbers of numbered cards = 9+9+9+9 = 36

∵ Probability = Number of favorable events/total events

∴ Probability both being numbered cards = $\frac{36c_{2} }{52c_{2} }$

       = (36 × 35)/(52 × 51)

       = 0.475