if two charges are separated by multiple media,what is electrostatic force between them?
Answers
the thickness of the dielectric is the same as the distance between the charges, r r , so the effective thickness is rK−−√ rK . If we put this in the force law we get:
F=14πϵ0Q1Q2(rK−−√)2=14πϵ01KQ1Q2r2 F=14πϵ0Q1Q2(rK)2=14πϵ01KQ1Q2r2
as we expect. The force is reduced by a factor of K K .
Now consider (b). To get the effective distance between the charges we have to add the distance through the air, r−t r−t , plus the effective thickness of the dielectric, tK−−√ tK , so the effective distance between the charges is:
d=(r−t)+tK−−√ d=(r−t)+tK
and the force is just:
F=14πϵ0Q1Q2d2=14πϵ0Q1Q2(r−t+tK−−√)2 F=14πϵ0Q1Q2d2=14πϵ0Q1Q2(r−t+tK)2
This is how you get the force when the space between the charges is only partially filled by the dielectric.
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I don know correctly about dis...
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