if two charges kept in air st a certain separation are now kept at the same in water of dielectric constant 80 tjen what happens to the force between them?
Answers
Answered by
1
Answer:
The total electric field E(net) is the sum of these two fields so net field will be reduced by a factor depending o dielectric constant of water. So the force f will go down to f/k = f/80 as k = 80 for water.
Similar questions