If two children of mass 30kg and 50 kg sit on a see saw form a distance of 2 m 2.5 m on which side of see saw does the man of 75 kg should sit to balance the see saw
Answers
Answered by
4
Answer:
see, the answer is quite simple!!
It's:
Anticlockwise moment= 30 x 2 + 50 x 2.5 = 60 + 125 = 185 kgf.m
Clockwise moment= 75 multiply by x kgf.m
By the principle of moments,
Anticlockwise moment= Clockwise moment
185= 75x
x= 185 divided by 75 which is equal to 2.47 m.
Therefore, the man should sit at a distance 2.47 m from the middle on the other side.
Explanation:
this was taught by my mom two days ago for my online maths exam!!
you're quite lucky!!
please mark me the brainliest!!
Similar questions
Math,
4 months ago
Math,
4 months ago
Computer Science,
4 months ago
Environmental Sciences,
9 months ago
Math,
11 months ago