Physics, asked by Amitp3186, 9 months ago

If two children of mass 30kg and 50 kg sit on a see saw form a distance of 2 m 2.5 m on which side of see saw does the man of 75 kg should sit to balance the see saw

Answers

Answered by varadarajanshruti
4

Answer:

see, the answer is quite simple!!

It's:

Anticlockwise moment= 30 x 2 + 50 x 2.5 = 60 + 125 = 185 kgf.m

Clockwise moment= 75 multiply by x kgf.m

By the principle of moments,

Anticlockwise moment= Clockwise moment

185= 75x

x= 185 divided by 75 which is equal to 2.47 m.

Therefore, the man should sit at a distance 2.47 m from the middle on the other side.

Explanation:

this was taught by my mom two days ago for my online maths exam!!

you're quite lucky!!

please mark me the brainliest!!

Similar questions