if two chords of a circle are equally inclined to the diameter through the point of intersection prove that chords are equal explain with proper references and I will mark you brainliest
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Given: AB is the diameter of the circle with center O.
∠BAC=∠BAD
TPT: AC=AD
construction; draw OM⊥AC and ON⊥AD
proof:
in the triangle OMA and triangle ONA,
∠OMA=∠ONA=90 deg (by the construction)
∠OAM=∠OAN
OA is common.
therefore by AAS congruency, triangles are congruent.
hence by the congruent property of the triangles OM = ON
⇒AC = AD [equal chords are equidistant from center ]
which is the required result.
hope this helps you.
cheers!!
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