Question

If two chords of a circle intersect within the circle prove that the segments of one chord is equal to corresponding segment of the other card

Answer 1

Answer:

If two equal chords of a circle intersect within the circle, prove that the segments of one chord are equal to corresponding segments of other chord. As chords are equal, perpendicular from centre would also be equal. $$OP$$ is common. Therefore , $$PB=PC$$ and $$AP=PD$$ is proved.